A block of mass m is pushed upwards with some initial velocity as shown in figure.

Column I | Column II | ||
(A) | Net force in horizontal direction | I. | Zero |
(B) | Net force In vertical direction | II. | |
(C) | Net force along the plane | III. |
|
(D) | Net force perpendicular to plane | IV. |
Match the direction of net force on the block given in Column I with the expression given in
Column II and choose the correct answer from the options given below. (
coefficient of
friction)
Text Solution
Verified by ExpertsB
Force of friction and
both are downwards.
Acceleration of the block is
down the plane
Now, net force on any direction is equal to,
(component of acceleration in that direction)
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